# Easy peasy perfect square

The question is to return true if the number is perfect square otherwise false.
A **perfect square** is an integer that is the square of an integer.
Javascript provides numerous ways to write a code for this. I will let you know that this is what I did:

```
const isSquare = (n) => {
return (Math.sqrt(n) === Math.ceil(Math.sqrt(n)));
}
```

Below is the solution that impressed me, because it is simple Math my brain couldn't get hold of first:

```
const isSquare = function(n){
return Math.sqrt(n) % 1 === 0;
}
```

And it is clever and also follows the best practices!

Checking the datatype would also work using `isInteger`

. But you never know when it would get obsolete! Languages change but the Math around remains the same! Choose better!

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